Continuing in such a fashion, one gets to -1(1) = -1 and -1(0) = 0. positive div divided by positive, positive, 6 2 3 6div 23 6236, divided by, 2, equals, 3. For example, in mapping products with (-1), one would get that -1(10) = -10, 10 units left of zero, -1(9) = -9, nine units left of zero and one unit right of -10 = -1(10). In fact, for any positive value of x, or if x equals zero, the sign would. This can also be demonstrated by mapping products of a negative number and other chosen numbers on a number line going from positive values to negative values. Absolute values are never negative, because absolute value only asks how far. A number can be checked for zero, positive. When you are adding a negative number to a positive number, then the value counts backward and takes the sign of the biggest number. Thus, as (a)(b) = (-a)(-b), (-a)(-b) is also positive. A number is said to be positive if it is greater than zero and it is said to be negative if it is less than zero. We know that a negative value plus a positive value always count backward and the sign depends on the bigger value sign. So the bank must take away a negative 10. Since (a) and (b) are positive, (a)(b) must be positive. So, two negatives make a positive, and if that satisfies you, then you are done Another Common Sense Explanation A friend is +, an enemy is A Bank Example Example: Last year the bank subtracted 10 from your account by mistake, and they want to fix it. Adds all number in the list, including negative numbers (net result is 16000). Since equality is transitive, meaning that things which are equal to the same are equal to each other, (-a)(-b) = (a)(b). Subtracts 9000 from 15000 (which equals 6000). Similarly, by starting with the same equation, x = (a)(b) + (-a)(b) + (-a)(-b), and factoring out (b) from the first two terms on the right side, gives x = (b) + (-a)(-b). Now, taking the expression x = (a)(b) + (-a)(b) + (-a)(-b) and factoring out (-a) from the last two terms gives x = (a)(b) + (-a). First, by definition -n = (-1)(n) for any number n.
0 kommentar(er)
